Changes

now add the DMS created during the heating and 82°C pasteurization to get the total calculated DMS: <code>Total DMS = 80 µg/L + 379 µg/L = 459 µg/L</code> Using the exact same wort composition but with a 60 minute boil, this example in "Principles of Brewing Science: A Study of Serious Brewing Issues" computes only 92 µg/L of DMS, mostly because a lot more of the SMM is converted to DMS during boilingwhich is volatilized, leaving less SMM to convert to DMS during cooling. Even with the higher SMM during cooling in the our heat pasteurized wort example, that hardly seems fair considering that the half-life of SMM is ~300 minutes at the pasteurization temperature of 82°C. If instead we just use the first equation that predicted how much SMM is decomposed into DMS during the heat pasteurization time, we get a different value of DMS. Using this equation might be more accurate for no-boil wort since it uses the half-life directly instead of averaging out the starting and ending temperatures. We'll use 95 minutes as our time (35 minutes for heating and pasteurizing, 60 minutes for cooling): <code>SMM into the fermenter = 1,000 µg/L x 2^{-(95 min/300 min)} = 1,000 x 2^-0.32 = 1,000 x 0.8 = 800 µg/L </code> and  <code>DMS into the fermenter = 1,000 µg/L - 800 µg/L = 200 µg/L </code> Another example will show that cutting the time down that the wort is exposed to 82°C will also lower the DMS. We'll estimate that it takes 45 minutes to heat the wort to 82°C, pasteurize for 15 minutes, and then cool to pitching temperature: <code>SMM = 1,000 µg/L x 2^{-(45 min/300 min)} = 1,000 x 2^-0.15 = 1,000 x 0.9 = 900 µg/L </code> and  <code>DMS = 1,000 µg/L - 900 µg/L = 100 µg/L </code> Considering again the large impact that temperature has on the half-life of SMM, 100 µg/L is still probably a gross overestimation of DMS. To see this, we'll calculate this again, but at 76°C (~600 minute half-life): <code>SMM = 1,000 µg/L x 2^{-(45 min/600 min)} = 1,000 x 2^-0.075 = 1,000 x 0.95 = 950 µg/L </code> and  <code>DMS = 1,000 µg/L - 900 µg/L = 50 µg/L </code>